Correct Answer - B::D
Wire of length `L` is bent in the form of a circle . Then perimeter of the circle
` 2pir = L ` rArr ` r= (L)/(2 pi)
:. Area of the circle ` = pir^(2) = (piL^(2))/( 4 pi^(2)) = ( L^(2))/(4 pi)`
Magnetic moment of a loop in which current `i` flows is given by
` M = iA = (iL^(2))/(4 pi)`