Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
67 views
in Physics by (92.0k points)
closed
The electric potential decreases unifromly from 120 V to 80 V as one moves on the x-axis from x=-1 cm to x=+1 cm. The electric field at the origin
A. must be equal to `20 V cm^-1`
B. must be equal to `20 Vm^-1`
C. may be greater than `20 Vm^-1`
D. may be less than `20 V cm^-1`

1 Answer

0 votes
by (92.8k points)
 
Best answer
Correct Answer - c
`E_x = (d V)/(d x) = (120 - 80)/(2) = 20 Vm^-1`
There may be the y - and z - components of field also.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...