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Solve the following equations:

i. \(\cfrac{y}{7} +\cfrac{y-4}{3}=2\)

ii. 13x – 5 = \(\cfrac{3}{2}\)

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 i. \(\cfrac{y}{7} +\cfrac{y-4}{3}=2\)

 ........[Multiplying both the sides by 21]

 ii. 13x – 5 = \(\cfrac{3}{2}\)

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