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Solve the following equation:

\(\cfrac{y-4}{3}+3y =4\)

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\(\cfrac{y-4}{3}+3y =4\)

\(\cfrac{y-4}{3}\)× 3 + 3y × 3 = 4 × 3

…[Multiplying both the sides by 3] 

∴ y – 4 + 9y = 12

∴ 10y – 4 = 12 

∴ 10y – 4 + 4=12 + 4 

…[Adding 4 on both the sides] 

∴10y = 16

∴ \(\cfrac{10y}{10}=\cfrac{16}{10}\)…[Dividing both the sides by 10]

∴ y = \(\cfrac{8}{5}\)

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