# Solve the following equations: (y-4)/3 + 3y = 4

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Solve the following equation:

$\cfrac{y-4}{3}+3y =4$

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$\cfrac{y-4}{3}+3y =4$

$\cfrac{y-4}{3}$× 3 + 3y × 3 = 4 × 3

…[Multiplying both the sides by 3]

∴ y – 4 + 9y = 12

∴ 10y – 4 = 12

∴ 10y – 4 + 4=12 + 4

…[Adding 4 on both the sides]

∴10y = 16

∴ $\cfrac{10y}{10}=\cfrac{16}{10}$…[Dividing both the sides by 10]

∴ y = $\cfrac{8}{5}$