\(\cfrac{y-4}{3}+3y =4\)
\(\cfrac{y-4}{3}\)× 3 + 3y × 3 = 4 × 3
…[Multiplying both the sides by 3]
∴ y – 4 + 9y = 12
∴ 10y – 4 = 12
∴ 10y – 4 + 4=12 + 4
…[Adding 4 on both the sides]
∴10y = 16
∴ \(\cfrac{10y}{10}=\cfrac{16}{10}\)…[Dividing both the sides by 10]
∴ y = \(\cfrac{8}{5}\)