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A metal block has the dimensions 10 cm × 5 cm × 2 cm and the density of the metal is 8 × 103 kg/m3. It is kept on a table with the face 10 cm × 5 cm in contact with the table. Find the force and pressure exerted by the block on the table. (g = 9.8 m/s2 )

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Data : 1 = 10 cm, b = 5 cm,

h = 2 cm, p= 8 × 10 kg/m3, g = 9.8 m/s2

A = lb = 10cm × 5cm = 50cm2 = 50 × 104m2 

= 5 × 10-5 m2 , force =?, pressure = ? 

Volume of the block = lbh = 10 cm × 5 cm × 2 cm

= 100 cm3 = 100 × 10-6 m3 = 1 × 10-4 m3 

Mass of the block = volume × density 

(∵ density = mass/volume) 

∴Mass of the block, 

m = 1 × 10-4 m3 × 8 × 103 kg/m3 = 0.8 kg 

Weight of the block = mg = 0.8 kg × 9.8 m/s2 = 7.84 N 

∴ The force exerted by the block on the table = 7.84 N. 

force 7.84 N

Pressure = \(\cfrac{force}{area}\) = \(\cfrac{7.84N}{5\times10^{-3}\,m^2}\)

= 1.568 × 103 N/m2 or 1.568 × 103 Pa 

The pressure exerted by the block on the table 

= 1.568 × 10 N/m2 or 1.568 × 103 Pa.

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