Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
584 views
in Number System by (33.1k points)
closed by

i. \(4\sqrt{12}\) - \(\sqrt{75}\) \(7\sqrt{48}\) 

4√(12) - √(75) - 7√(48)

ii. \(2\sqrt{48}\) - \(\sqrt{75}\) - \(\frac{1}{\sqrt3}\) 

2√48 - √75 - 1/√3

1 Answer

+1 vote
by (33.6k points)
selected by
 
Best answer

i. \(4\sqrt{12}\) - \(\sqrt{75}\) \(7\sqrt{48}\)  

4√(12) - √(75) - 7√(48)  

 

ii.   \(2\sqrt{48}\) - \(\sqrt{75}\) - \(\frac{1}{\sqrt3}\) 


 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...