Question

A hydrocarbon `C_6 H_12` decolourises bromine solution and yields `n-`hexane on hydrogenation. On oxidation with `KMnO_4` it affords two different monobasic acids of the type `R-COOH`. The compound is :
A. Cyclohexene
B. 2-Hexene
C. 1-Hexene
D. 3-Hexene

Answer 1

Correct Answer - D
`1 D.U` suggests alkene (decolourises `Br_2` solution), gives `n-`hexane on hydrogenation. Two different acids on oxidation suggest that `(C=C)` bond is not symmetrical. So, the compound `(A)` is :
.