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Consider the spectral line resulting from the transition `n = 2 rarr n = 1 ` in the atoms and ions given . The shortest wavelength is produced by
A. hydrogen atom
B. deuterium atom
C. singly ionization helium
D. doubly ionized lithium

1 Answer

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Best answer
Correct Answer - D
We know that
`(1)/(lambda) = R z^(2) [(1)/(n_(2)^(2)) - (1)/(n_(1)^(2))] implies (1)/(lambda) prop z^(2)`
`lambda` is shortest when `1//lambda` is i.e., when `z` is big `z` is highest for lithum.

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