# A stream of protons and deuterons in a vacuum chamber enters a uniform magnetic field. Both protons and deuterons have been subjected to same accelera

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A stream of protons and deuterons in a vacuum chamber enters a uniform magnetic field. Both protons and deuterons have been subjected to same accelerating potential, hence the kinetic energies of the particles are the same. If the ion-stream is perpendicular to the magnetic field and the protons move in a circular path of radius 15 cm, find the radius of the path traversed by the deuterons. Given that mass of deuteron is twice that of a proton.

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The radius r of the path is given by
(mv^2)/r=qvB or r=(mv)/(qB)
For proton, r_p=(m_pv_p)/(q_pB)
For deuteron, r_d=(m_dv_d)/(q_dB)
:. (r_d)/(r_p)=(m_dv_d)/(m_pv_p)xx(q_pB)/(q_dB)….(i)
Given that 1/2m_pv_p^2=1/2m_dv_d^2 also q_b=q_d
Now (v_d)/(v_p)=((m_p)/(m_d))^(1//2).....(ii)
Substituting the value of v_d//v_p from Eq. (i) in Eq.(i) we get
(r_d)/(r_p)=(m_d)/(m_p) ((m_p)/(m_d))^(1//2)=((m_d)/(m_p))^(1//2)=sqrt2 (because m_d=2m_p)
or r_d=sqrt2.r_p=1.414xx0.15=0.212m