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Two metal pieces having a potential difference of `800V` are `0.02 m` apart horizontally. A particle of mass `1.96xx10^(-15) kg` is suspended in equilibrium between the plates. If the `e` is the elementary charge, then charge on the particle is
A. `e`
B. `3e`
C. `6e`
D. `8e`

1 Answer

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Best answer
Correct Answer - b
For equilibrium `mg=qE`
`:. 1.96xx10^(-15)xx9.8=qxx((800)/(0.02))`
`implies q=(1.96xx10^(-15)xx9.8xx0.02)/(800)`
`implies nxx1.6xx10^(-19)=(1.96xx10^(-15)xx9.8xx0.02)/(800)implies n=3`.

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