Question

The diagram given below shows a solenoid carrying time varying current `l= l_(0)t`. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is

A. `((2M+L)I_(0))/(R)`
B. `(MI_(0))/(R)`
C. `((2M-L)I_(0))/(R)`
D. `((M+L)I_(0))/(R)`

Answer 1

Correct Answer - B
`phi=MI=MI_(0)t`
Hence, induced emf `e=(d phi)/(dt)=MI_(0)`
Current through ring `=e/R=(MI_(0))/(R)`.