Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
87 views
in Physics by (93.7k points)
closed by
A telescope has an objective of focal length `50cm` and an eyepiece of focal length `5cm.` The least distance of distinct vision is `25cm.` The telescope is focused for distinct vision on a scale `2m` away from the objective. Calculate (a) magnification produced and (b) separation between objective and eyepiece.
A. `75cm`
B. `60 cm`
C. `71 cm`
D. `74 cm`

1 Answer

0 votes
by (93.9k points)
selected by
 
Best answer
Correct Answer - C
`f_(o)=50cm, f_(e)=5cm, D=25cm, `and `u_(o)=200cm`.
Separation between the objective and the eye lens is
`L=(u_(o)f_(o))/((u_(o)-f_(o)))+(f_(e)D)/((f_(e)+D))`
`=(200xx50)/((200-50))+(5xx25)/((5+25))=71cm`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...