Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
61 views
in Physics by (72.2k points)
closed by
Two coherent light sources `S_1` and `S_2 (lambda=6000Å)` are `1mm` apart from each other. The screen is placed at a distance of `25cm` from the sources. The width of the fringes on the screen should be
A. (a) `0.015cm`
B. (b) `0.025cm`
C. (c) `0.010cm`
D. (d) `0.030cm`

1 Answer

0 votes
by (118k points)
selected by
 
Best answer
Correct Answer - A
`beta=(6000xx10^(-10)xx25xx10^-2)/(10^-3)`
`=150000xx10^-9=0.15xx10^-9`
`=0.15xx10^-3m=0.015cm`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...