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A double slit arrangement produces interference fringes for sodium light `(lambda=589nm)` that have an angular separation of `3.50xx10^-3` radian. For what wavelength would the angular separation be 10% greater?
A. (a) `527nm`
B. (b) `648nm`
C. (c) `722nm`
D. (d) `449nm`

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Correct Answer - B
Angular separation `=lambda/d`
For angular separation to be 10% greater `lambda` should be 10% greater.
New wavelength is `(589+(589)/(10))nm`
or `(589+58.9)nm`, i.e., `647.9nm`, i.e., 648nm`

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