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A solenoid of length `50cm`, having `100` turns carries a current of `2*5A`. Find the magnetic field, (a) in the interior of the solenoid, (b) at one end of the solenoid.
Given `mu_0=4pixx10^-7WbA^-1m^-1`.

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Here, `I=2*5A`,
`n=100//0*50=200m^-1`
(a) `B=mu_0nI=4pixx10^-7xx200xx2*5`
`=6*28xx10^-4T`
(b) `B=(mu_0nI)/(2)=(4pixx10^-7xx200xx2*5)/(2)`
`=3*14xx10^-4T`

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