Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
65 views
in Physics by (72.2k points)
closed by
Two circular coils X and Y, having equal number of turns and carrying currents in the same sense, subtend same solid angle at point O. If the smaller coil X is midway between O and Y and if we represent the magnetic induction due to bigger coil Y at O as `B_y` and the due to smaller coil X at O as `B_x`,then find the ratio `B_x//B_y`.
image
A. `1:1`
B. `2:1`
C. `1:2`
D. `1:4`

1 Answer

0 votes
by (118k points)
selected by
 
Best answer
Correct Answer - C
Since the two coils subtend the same solid angle at O, hence area of coil `D=4` x area of coil C,
[because solid angle `=(area)/((_|_r distance)^2)`].
Therefore, radius of coil `D=2xx` radius of coil C
`:. B_D=(mu_0)/(4pi)(2piI(2r)^2)/([(2r)^2+a^2]^(3//2))`
image
`B_C=(mu_0)/(4pi)(2piIr^2)/([r^2+(a//2)^2]^(3//2))`
`:. (B_D)/(B_C)=(4)/((4r^2+a^2)^(3//2))xx[(4r^2+a^2)/(4)]^(3//2)=4/8=1/2`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...