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The ferequency `1057 MHz` of radiation arising from two close energy levels in hydrogen belong to:
A. radio waves
B. infrared waves
C. micro waves
D. `omega`-rays

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Correct Answer - a
`v=1057 MHz`
`lambda=(c)/(v)=(3xx10^(8))/(1057xx10^(6))m`
`=0.28m=28cm`(radiowaves)

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