Question

Calculate the dispersive power for crown glass from the given data
`mu_(v)=1.523` and `mu_(r)=1.5145`.

Answer 1

Here, `mu_(v) = 1.5230, mu_(r ) = 1.5145, omega = ?`
mean refractive index, `mu = (mu+(v) + mu_(r ))/(2) = (1.5145 + 1.5230)/(2) = 1.5187`
`omega = (mu_(v) - mu_(r ))/(mu - 1) = (1.5230 - 1.5145)/(1.5187 - 1) = (0.0085)/(0.5187) = 0.0163`