Question

A closed container of volume 0.02 m³ contains a mixture of neon and argon gases at a temperature 27°C and pressure 1 x 10⁵ Nm^-2 . The total mass of mixture is 28 g. If the gram molecular weight of neon and argon are 20 and 40 respectively, find the masses of individual gases in the container, assuming them to be ideal.

Answer 1

Given V= 0.02 m³ , T = 300 K, P = 1 x 10⁵ Nm^-2 , R = 8.314 J 

Let a and b g be mass of Ne and Ar respectively.

Thus a+b = 28

Also total mole of Ne and Ar = a/20 + b/40

Thus from PV - nRT