Question

The total energy of eletcron in the ground state of hydrogen atom is `-13.6 eV`. The kinetic enegry of an electron in the first excited state is
A. `6.8 eV`
B. `13.6eV`
C. `1.7eV`
D. `3.4eV`

Answer 1

Correct Answer - D
Total energy =P.E. + K.E.
`=-13.6 eV=-2KE+KE=-KE`
`:.KE=+13.6eV`
In first excited state, n=2
`:. K.E. =13.6/(2^(2))eV=3.4eV`