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Construct a triangle ABC with BC = 7 cm, ∠B = 60°and AB = 6 cm. Construct another triangle whose sides are 3/4 of the corresponding sides of ΔABC.

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Steps of construction :

1. Draw a line segment BC = 7 cm.

2. At point B draw a line BA making an angle of 60°.

3. With centre C mark an arc A of length 6 cm.

4. Join CA.

5. Draw a ray BX making an acute angle with BC.

6. Locate four points B1, B2, B2 and B4, on the line segment BX at equal distance.

7. Join B4C. Draw a parallel line through B, to B4C intersecting line segment BC at C'.

8. Through C' draw a line parallel to AC intersecting extended line segment AB at A'.

Hence ΔA'BC' is the required triangle.

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