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8 litre of H2 and 6 litre of Cl2 are allowed to react to maximum possible extent. Find out the final volume of reaction mixture. Suppose P and T remains constant throughout the course of reaction. 

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H2 + Cl2 -----> 2HCl

Volume before reaction  8 litre      6 litre

Volume after reaction       2            0              12 litre

Volume after reaction =  volume of H2 left + volume of HCI formed

= 2 + 12

= 14 litre

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