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in Chemistry by (31.5k points)

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 litre (Measured at STP) of this welding gas is found to weigh 11.6 g. Calculate : (i) empirical formula, (ii) molar mass of the gas, and (iii) molecular formula.

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Best answer

Molecular mass of welding gas = 11.6 x 22.4/10 = 25.98

CO2 and H2O are obtained from welding gas combustion in water.

g-atoms of C in gas  = 3.38/44 = 0.077

g-atoms of H in gas = 0.690 x 2/18 = 0.077

Ratio of C and H atoms in gas is 1 : 1

Thus, empirical formula of welding gas is CH 

Empirical formula mass of welding gas = 13 

Molecular mass = (empirical formula mass) x n 

n = 25.98/13 = 2

Molecular formula = 2 x empirical formula = 2 x (CH) = C2H2

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