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in Algebraic Expressions by (32.3k points)
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Subtract the second expression from the first. 

i. (4xy – 9z); (3xy – 16z) 

ii. (5x + 4y + 7z); (x + 2y + 3z) 

iii. (14x2 + 8xy + 3y2); (26x2 – 8xy – 17y2

iv. (6x2 + 7xy + 16y2); (16x2 – 17xy) 

v. (4x + 16z); (19y – 14z + 16x)

1 Answer

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Best answer

i. (4xy – 9z) – (3xy – 16z) 

= 4xy – 9z – 3xy + 16z 

= (4xy – 3xy) + (16z – 9z) 

= xy + 7z 

ii. (5x + 4y + 7z) – (x + 2y + 3z) 

= 5x + 4y + 7z – x – 2y – 3z 

= (5x – x) + (4y – 2y) + (7z – 3z) 

= 4x + 2y + 4z

iii. (14x2 + 8xy + 3y2) – (26x2 – 8xy – 17y2) 

= 14x2 + 8xy + 3y2 – 26x2 + 8xy + 17y2 

= (14x2 – 26x2) + (8xy + 8xy) + (3y2 + 17y2

= -12x2 + 16xy + 20y2 

iv. (6x2 + 7xy + 16y2) – (16x2 – 17xy) 

= 6x2 + 7xy + 16y2 – 16x2 + 17xy 

= (6x2 – 16x2) + (7xy + 17xy) + 16y2 

= -10x2 + 24xy + 16y2 

v. (4x + 16z) – (19y – 14z + 16x) 

= 4x + 16z – 19y + 14z – 16x 

= (4x – 16x) – 19y + (16z + 14z) 

= -12x – 19y + 30z

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