Question

Solve the following equations:

i. y – 5 = 1 

ii. 8 = t + 5 

iii. 4x = 52 

iv. 19 = m – 4

Answer 1

i. y – 5 = 1 

∴ y – 5 + 5 = 1 + 5 

…. (Adding 5 to both sides) 

∴ y + 0 = 6 

∴ y = 6

ii. 8 = t + 5 

∴ 8 – 5 = t + 5 – 5 

……(Subtracting 5 from both sides) 

∴ 8 + (-5) = t + 0 

∴ 3 = t 

∴ t = 3

iii. 4x = 52

∴ \(\cfrac{4x}{4} = \cfrac{52}{4}\)

…. (Dividing both sides by 4) 

∴ 1x = 13 

∴ x = 13

iv. 19 = m -4 

∴ 19 + 4 = m – 4 + 4 

…. (Adding 4 to both sides) 

∴ 23 = m + 0 

∴ m = 23