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The resistance of a bulb filmanet is `100Omega` at a temperature of `100^@C`. If its temperature coefficient of resistance be 0.005 per `.^@C`, its resistance will become `200 Omega` at a temperature of
A. `200^(@)C`
B. `300^(@)C`
C. `400^(@)C`
D. `500^(@)C`

1 Answer

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Best answer
Correct Answer - B
Let resistance of bulb filament is `R_(0)` at `0^(@)C`, then from expression
`R=R_(0)(1+alphaDeltaT)`
`:. 100=R_(0)(1+0.005xx100)`
`200=R_(0)(1+0.005xxx)`
Where `x` is temperature in `.^(@)C` at which resistance becomes `200 Omega`
Dividing the above two equation
`200/100=(1+0.005 x)/(1+0.005xx100)implies x=400^(@)C`

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