Here, `A= 15 mm^(2) = 15xx10^(-6) m^(2)`,
`rho=7.6xx10^(-8) Omega m,alpha =5xx10^(-3).^(@)C^(-1)`,
`l_(0)=2 km = 2000m, t_(1)=0^@C,t_(2)=60^@C`,
`R_(0)=rhol/A=((7.6xx10^(-8))xx2000)/(15xx10^(-6)) = 10.12Omega`
`R_(60)=R_(0)[1+alpha (t_(2)-t_(1))]`
`=10.12 [1+5xx10^(-3) xx60]`
`=10.12 xx1.3 =13.16 Omega`