Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
109 views
in Physics by (98.1k points)
closed by
The galvanometer, in each of the two given circuits does not show any deflection. Find the ratio of the resistors `R_(1)` and `R_(2)` used in these two circuits.
image

1 Answer

0 votes
by (97.7k points)
selected by
 
Best answer
In circuit 1, the Wheatstone bridge is in balanced state so,
`4/R_(1) = 6/9`
or `R_(1) = (4xx9)/6 = 6 Omega`
In circuit 2, the positions of galvanometer and battery are interchanged but the galvanometer shows no defelction, means the bridge is in balanced state, so
`6/12 = R_(2)/8 or R_(2) = (6xx8)/12 = 4 Omega`
`R_(1)/R_(2) = 6/4 = 3/2` or `R_(1) : R_(2) = 3:2`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...