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In a house having `220 V` line , the following appliances are operating :
(i) a ` 60 W` bulb, (ii) a `1000 W` heater , and (iii) a` 40 W` radio.
Calculate (a) the current drawn by the heater and (b) the current passing through the fuse in the main line.

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Correct Answer - `(50)/(11)A`,5A`
(a) current drawn by heated
`l_(1) = (P_(1))/(V) = (1000)/(220) = (50)/(11)A`
(b) Current drawn by bulb `l_(2) = (P_(2))/(V) = (60)/(220) = (3)/(11)A`
(b) Current drawn by radio `l_(3) = (P_(3))/(V) = (40)/(220) = (2)/(11)A`
current passing through the fase line
`= l_(1) + l_(2) + l_(3) = (50)/(11) + (5)/(11) + (2)/(11) = 5A`

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