Question

4 g of NaOH are present in 0.1 dm³ solution have specific gravity 1.038 g/mL. Calculate : 

(a) mole fraction of NaOH; 

(b) molality of NaOH solution; 

(c) molarity of NaOH solution; 

(d) normality of NaOH solution.

Answer 1

Volume of solution = 0.1 dm² = 1/10 litre = 100 mL

Weight of solution = 100 x 1.038 = 103.8 g

Weight of water = weight of solution - weight of NaOH 

= 103.8-4 

= 99.8 g