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Given eqn.

x2 + 5x + 6, a = 1, b = 5, c = 6

Sum of roots (α + β) = -b/a = -5/1 = -5

Product of roots (αβ) = c/a = 6/1 = 6

1/α2 + 1/β2 = (α2β2)/α2β2

= {(α + β)2 - 2αβ}/(αβ)2

= {(-5)2 - 2(6)}/(6) [ a2 + b2 = (a + b)2 - 2ab ]

= (25 - 12)/36

= 13/36

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