Question

For a concave mirrorr, if real image is formed the graph between `(1)/(u)` and `(1)/(v)` is of the form
A.
B.
C.
D.

Answer 1

Correct Answer - A

`(1)/(v)+(1)/(u)=(1)/(f)impliesy+x=(1)/(f)`
`y=(-x+1)/(f)=mx+c`
`(1)/(v)` v/s `(1)/(u)` graph will be straight line of slope `-1` and intercept `(1)/(f)`.
Here. `(1)/(v),(1)/(u),(1)/(f)` represents magnitudes