Correct Answer - A
`n_1sinC=n_2sin90^@impliessinC=n_2//n_1`
`C=sin^-1(n_2//n_1)`
Refraction at AB: `n_2sinalpha=n_1sinr`
`sinr=n_2/n_1sinalpha` …(i)
`r+i=90^@impliesr=90^@-i`
For T.I.R. on AD:
`igeC`
`sinigesinCimpliessinigen_2//n_1`
`igesin^-1(n_2//n_1)`
`cosigecos[sin^-1(n_2//n_1)]`
`sinrlecos[sin^-1(n_2//n_1)]`
`n_2/n_1sinalphalecos[sin^-1(n_2//n_1)]`
`sinalphalen_1/n_2cos[sin^-1(n_2//n_1)]`
`alphalesin^-1[n_1/n_2cos{sin^-1(n_2//n_1)}]`
`alpha_(max)=sin^-1[n_1/n_2cos{sin^-1(n_2//n_1)}]`