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An ideal coil of 10H is connected in series with a resistance of `5(Omega)` and a battery of 5V. 2second after the connections is made, the current flowing in ampere in the circuit is
A. `(I-e)`
B. `e`
C. `e^(-1)`
D. `(I-e^(-1))`

1 Answer

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Best answer
Correct Answer - D
`I_(0) = (E)/(R ) = 1A , tau = (L)/(R ) = (10)/(5) = 2s, :. (I = 1-e^(-1))A`

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