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in Mathematics by (54.0k points)

The locus of the midpoints of the chords of the circle x2+ y2 + 4x - 6y - 12 = 0 which subtend an angle of π/3 radians at its circumference is:

(A) (x - 2)2 + (y + 3)2 = 6.25 

(B) (x + 2)2 + (y - 3)2 = 6.25

(C) (x + 2)2 + (y - 3)2 = 18.75 

(D) (x + 2)2 + (y + 3)2 = 18.75

1 Answer

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Best answer

(B) (x + 2)2 + (y - 3)= 6.25

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