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Complete the following nuclear reactions : (i) (208,84)Po → (204,82)Pb + ........

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Complete the following nuclear reactions :

(i) 20884Po →  20482Pb + ........

(ii) 3215P →  3216S + ..........

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We have

(i) 20884Po →  20482Pb + 42He + Q

(Also accept if Q is not written)

(ii) 3215P →  3216S + 0-1e + v

[Also accept if r.r is not written]

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