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On a sheet of card paper, draw a right-angled triangle of sides 3 cm, 4 cm and 5 cm. Construct a square on each of the sides. Find the area of each of the squares and verify Pythagoras’ theorem.

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Area of square ABLM = l(AB)2 = 32 = 9 sq.cm 

Area of square BCPN = l(BC)2 = 42 = 16 sq.cm 

Area of square ACQR = l(AC)2 = 52 = 25 sq.cm 

Now, 25 = 16 + 9

i.e. 52 = 42 + 32 

∴ l(AC)2 = l(BC)2 + l(AB)2 

∴ (hypotenuse)2 = (base)2 + (height)2

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