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A nuclear of mass `M +deltam ` is at rest and decay into two daughter nuclei of equal mass `(M)/(2)` each speed is `c`
The speed of daughter nuclei is
A. `c(Delta m)/(M+Delta m)`
B. `csqrt((2 Delta m)/(M))`
C. `csqrt(( Delta m)/(M))`
D. `csqrt((Delta m)/(M+Delta m))`

1 Answer

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Best answer
According to conservation of momentum
`0 = (M)/(2) V_(1) - (M)/(2)V_(2), V_(1) = V_(2)`,
`Deltamc^(2) = (1)/(2) (M)/(2) V_(1)^(2) + (1)/(2).(M)/(2) V_(2)^(2)`

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