`K_(f)` for waer is `1.86 K kg mol^(-1)`. If your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol

`K_(f)` for waer is `1.86 K kg mol^(-1)`. If your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C`?
A. `27g`
B. `72g`
C. `93g`
D. `39g`

`K_(f)` for waer is `1.86 K kg mol^(-1)`. If your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` m

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