Question

A compound `H_(2)X` with molar weigth of 80g is dissolved in a solvent having density of `0.4 g mol^(-1)`. Assuming no change in volume upon dissolution, the molarity of a `3.2` molar solution is

Answer 1

Correct Answer - 8
Molarity `= 3.2 M`
Let volume of solution `= 1000 ml =` volume of solvent
Mass of solvent `= 1000 xx 0.4 = 400 gm`
`m_(solute) = 3.2` mole
Molality (m) `=(3.2)/(400//1000) = 8`