LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
22 views
in Physics by (84.0k points)
closed by
Two objects of masses `m` and `4m` are at rest at an infinite separation. They move towards each other under mutual gravitational attraction. If `G` is the universal gravitaitonal constant, then at separation `r`
A. the total mechanical energy of the two objects is zero
B. their relative velocity is `sqrt((10Gm)/(r))`
C. the total kinetic energy of the object is `(4Gm^(2))/(r)`
D. their relative velocity is zero.

1 Answer

0 votes
by (86.4k points)
selected by
 
Best answer
Correct Answer - A::B::C
By applying low of conservation of momentum image
`mv_(1)-4mv_(2)=0impliesv_(1)=4v_(2)`
by applying conservation of energy `(1)/(2)mv_(1)^(2)+(1)/(2)4mv_(2)^(2)=(Gm4m)/(r)implies10mv_(2)^(2)=(G4m^(2))/(r)impliesv_(2)=2sqrt((Gm)/(10r))`
`therefore` total kinetic energy `=(4Gm^(2))/(r)`
Relative velocity for the particle `impliesv_(rel)=|vecv_(1)-vecv_(2)|=5v_(2)=sqrt((10Gm)/(r))`
Mechanical energy of system `=0=` constant by using reduced mass concept
`(1)/(2)muv_(rel)^(2)=(Gm(4m))/(r)` where `mu=((m)(4m))/(m+4m)=(4)/(5)mimpliesv_(rel)=sqrt((10Gm)/(r))`
Also total KE system `=(G(m)(4m))/(r)=(4Gm^(2))/(r)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...