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When 3.725 g of KCl is dissolved in excess of water, the amount of heat absorbed is X kJ. Calculate the enthalpy of solution of KCI.

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KC1 + aq. →  KCaq ; H= ?

3.725 g KCl on dissolution absorbed heat = X kJ

74.5 g KCl on dissolution absorbed heat - x (74.5)/3.725 = 20 x

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