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The outer electrons configuration of `Lu` (Atomic No.,71)` is :

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The outer electrons configuration of `Lu` (Atomic No.,71)` is :
A. `4F^(3) 5d^(5) 6s^(2)`
B. `4f^(8)5d^(0) 6s^(2)`
C. `4f^(4)5d^(4) s^(2)`
D. `4f^(14)5d^(1)6s^(2)`
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1 Answer

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Correct Answer - 4
Lutetium `(_71Lu)[Xe]^(54)4f^(14)5d^(1)6s^(2)`
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