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Prove the following :

tan-1\(\sqrt{\cfrac{1-cos\,θ}{1+cos\,θ}}\) = \(\cfrac{θ}{2}\), if θ ∈ (0, π)

tan-1 √(1-cos θ/1+ cosθ) , if θ ∈ (0, π)

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Best answer

tan-1\(\sqrt{\cfrac{1-cos\,θ}{1+cos\,θ}}\) = \(\cfrac{θ}{2}\)

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