Correct Answer - C
Initial charge on 6 mF capacitor
`= (3 xx 6)/(3+6) xx 4 = 8 mC`
final charge on 6mF capacitor `= 6 xx 6 = 25 mC` charge passing through cell (in direction aided by cell) `= q_(f) -q_(i) = Dq = 24 - 8 = 16 mC` work done by cell = Dqe `= 16 xx 4 = 64 mJ`