Question

`alpha`- maltose `(C_(12)H_(22)O_(11))` can be hydrolysed to glucose `(C_(6)H_(12)O_(6))` according to the following reaction.
`C_(12)H_(22)(O_(11)(aq)+H_(2)O(l)to2C_(6)H_(12)O_(6)(aq)`
Given:
Standard enthalpy of formation of `C_(12)H_(22)O_(11)(aq)=-2238(kJ)/(mol)`
Standard enthalpy of formation of `H_(2)O(l)=-285(kJ)/(mol)`
Standard enthalpy of formation of `C_(6)H_(12)O_(6)(aq)=-1263(kJ)/(mol)`
Which of the following statements (s) is/are true?
A. the hydrolysis of `alpha`- maltose is exothermic.
B. Heat liberated in combustion of 1.0 mol of `alpha`- moltose is greater than the heat liberated in combustion of 2.0 mol of glucose.
C. Increasing temperature will increase the degree of hydrolysis of `alpha`- maltose
D. The hydrolysis of `alpha`- maltose follow `1^(st)` order kinetics.

Answer 1

Correct Answer - A::B::D
(A). `DeltaH=[2(-1263)]-[(-2238)+(-285)]=-3kJ`
(B). `C_(12)H_(22)O_(11)+12O_(2)to12CO_(2)+11H_(2)O`
`{C_(6)H_(12)O_(6)6O_(2)to6CO_(2)+6H_(2)O}xx2`
`C_(12)H_(22)O_(11)+H_(2)Oto2C_(6)H_(12)O_(5),DeltaH=-3kJ` ltbr. (C). Hydrolysis is exothermic `Tuarrhdarr`
(D). Concentration becomes one-fourth in equal tim interval. Hence `1^(st)` order.