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Two coherent light sources `S_1` and `S_2 (lambda=6000Å)` are `1mm` apart from each other. The screen is placed at a distance of `25cm` from the sources. The width of the fringes on the screen should be
A. 0.015 cm
B. 0.025 cm
C. 0.010 cm
D. 0.030 cm

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Best answer
Correct Answer - A
`beta =(6000xx10^(-10)xx25 xx10^(-2))/(10^(-3))`
`:. lamda_("glass") lt lamda_("air") (because C_("glass") lt C_("air"))`.

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