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If `f(x)` is a polynomial such that `(alpha+1)f(alpha)-alpha=0AA alpha epsilon Nuu{0}, alpha le n`, then
A. `f(76)` is 1
B. `f(21)` is `10/11`
C. `f(37)` is `1/7`
D. `f(148)` is `9/13`

1 Answer

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Best answer
Correct Answer - A::B
`g(x)=(x+1)f(x)-xs`
`g(x)=0` for `x=0,1,2,……..n`
`g(x)=ax(x-1)…….(x-n)`
`:. (f(x)=((-1)^(n+1)x.(x-1)…..(x-n))/(|___(n+1))+x)/(x+1`

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