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in Matrices by (31.1k points)
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Find AB,

If A = \(\begin{bmatrix} 1 & 2 & 3 \\[0.3em]1 & -2 &-3 \\[0.3em] \end{bmatrix}\) and B = \(\begin{bmatrix} 1 & -1 \\[0.3em]1 & 2 \\[0.3em] 1& -2\end{bmatrix}\) 

Examine whether AB has inverse or not.

[1,2,3,1,-2,-3] 

[1,-1,1,2,1,-2]

1 Answer

+1 vote
by (30.3k points)
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Best answer

Given,

A = [1,2,3,1,-2,-3] and 

B = [1,-1,1,2,1,-2]

∴ A is a non-singular matrix.

Hence,

(AB)-1 exist.

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