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What are vertices of triangle the equation have whose side are x = y, 3y= x and find x+y= 8

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The given equations are

y = x ...(i)

3y = x ...(ii)

x+y = 8  ...(iii)

The two points satisfying (i) can be listed in a table as,

x 0 2
y 0 2

The two points satisfying (ii) can be listed in a table as,

x 3 -3
y 1 -1

The two points satisfying (iii) can be listed in a table as,

x 3 5
y 5 3

Now, the graph of equations (i), (ii) and (iii) can be drawn as,

It is seen that coordinates of the obtained triangle are A(0, 0), B(4, 4), C(6, 2).

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